1/x+5+3/x^2+x-20=2/x-4

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Solution for 1/x+5+3/x^2+x-20=2/x-4 equation: 



1/x+5+3/x^2+x-20=2/x-4

We move all terms to the left:

1/x+5+3/x^2+x-20-(2/x-4)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x-4)!=0

x∈R



We add all the numbers together, and all the variables

x+1/x+3/x^2-(2/x-4)-15=0

We get rid of parentheses

x+1/x+3/x^2-2/x+4-15=0

We calculate fractions

We do not support expression: x^3

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